The length of a rectangle is twice it’s width. If the area of the rectangle is 162m ^2,find its perimeter

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Question:

The length of a rectangle is twice it’s width. If the area of the rectangle is 162m ^2,find its perimeter

Answers

Answer:[tex]{ \tt{area = length \times width}} \\ { \tt{162 = 2w \times w}} \\ { \tt{162 = 2 {w}^{2} }} \\ { \tt{ {w}^{2} = 81}} \\ { \tt{w = 9}}[/tex]width, w = 9 mlength, l = 2 × 9 = 18 m[tex]{ \tt{perimeter = 2(l + w)}} \\ { \tt{p = 2(18 + 9)}} \\ { \tt{p = 2 \times 27}} \\ \\ { \underline{ \tt{ \: \: perimeter = 54 \: m \: \: }}}[/tex]

Answer:54 mStep-by-step explanation:First, find the width 162 = 2w × w 162 = 2w² w² = 162 ÷ 2 w = [tex] \sqrt{81}[/tex] w = 9 m┈Second, find the length l = w × 2 l = 9 × 2 l = 18 m┈Then, find the perimeter perimeter = 2(l + w) perimeter = 2(18 + 9) perimeter = 2(27) perimeter = 54 m

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