The length of a rectangle is 24 feet more than the width. The perimeter of the rectangle is 88 feet. What is the length and width of this rectangle?
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Question:
the length of a rectangle is 24 feet more than the width. The perimeter of the rectangle is 88 feet. What is the length and width of this rectangle?
Answers
The length of the rectangle is 34 feet.The given parameters;perimeter of the rectangle, P = 88 feet.let the width of the rectangle = wthen, the length of the rectangle, L = 24 + wThe length of the rectangle is calculated as follows;P = 2(L+ w)P = 2(24 + w + w)P = 2(24 + 2w)88 = 48 + 4wsubtract 48 from both sides of the equation;88 - 48 = 4w40 = 4ww = 10Now, solve for the length;L = 24 + wL = 24 + 10L = 34 feetThus, the length of the rectangle is 34 feet.Learn more here:https://brainly.com/question/18869010
Answer:W = 10 ftStep-by-step explanation:Represent the length by L and the width by W. Then L = W + 24.The perimeter is P = 2W + 2L, or 88 ft. Thus, after substituting L = W + 24,88 ft = 2W + 2(W + 24), or88 = 2W + 2W + 48, or, after reduction,44 = 2W + 24, or2W = 20, and so W = 10 ft
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