# The length of a rectangle is 24 feet more than the width. The perimeter of the rectangle is 88 feet. What is the length and width of this rectangle?

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The length of the rectangle is 34 feet.The given parameters;perimeter of the rectangle, P = 88 feet.let the width of the rectangle = wthen, the length of the rectangle, L = 24 + wThe length of the rectangle is calculated as follows;P = 2(L+ w)P = 2(24 + w + w)P = 2(24 + 2w)88 = 48 + 4wsubtract 48 from both sides of the equation;88 - 48 = 4w40 = 4ww = 10Now, solve for the length;L = 24 + wL = 24 + 10L = 34 feetThus, the length of the rectangle is 34 feet.Learn more here:https://brainly.com/question/18869010

Answer:W = 10 ftStep-by-step explanation:Represent the length by L and the width by W. Then L = W + 24.The perimeter is P = 2W + 2L, or 88 ft. Thus, after substituting L = W + 24,88 ft = 2W + 2(W + 24), or88 = 2W + 2W + 48, or, after reduction,44 = 2W + 24, or2W = 20, and so W = 10 ft