The length of a new rectangle playing field is 8 yards longer than a quadruple the width if the perimeter of the rectangle playing field is 368 yards what are the dimensions

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Question:

The length of a new rectangle playing field is 8 yards longer than a quadruple the width if the perimeter of the rectangle playing field is 368 yards what are the dimensions

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Answer:width = 35.2 yd; length = 148.8 ydStep-by-step explanation:Let the width = w.The length is 8 yd more than 4 times the width.length = 4w + 8perimeter = 2(length + width)perimeter = 2(4w + 8 + w)perimeter = 2(5w + 8)perimeter = 10w + 16perimeter = 368 yd10w + 16 = 36810w = 352w = 35.2length = 4w + 8length = 4(35.2) + 8length = 148.8 ydAnswer: width = 35.2 yd; length = 148.8 yd

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