The electrostatic force between two objects is 40N. if the charge of one object is cut in half, and the distance is doubled, what is the new force?
1 answer
Question:
the electrostatic force between two objects is 40N. if the charge of one object is cut in half, and the distance is doubled, what is the new force?
Answers
Answer:F1 = K Q1 Q2 / R1^2F2 = K Q1 / 2 * Q2 / (2 R1)^2F2 / F1 = 1/2 / 4 = 1/8The new force is 5N (1/2 due to charge and 1/4 due to distance)
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