The disorder known as cystic fibrosis (CF) is inherited in a recessive autosomal manner. In populations of Northern European descent, the frequency of people with CF is about 1 in 2,500. Assuming Hardy-Weinberg equilibrium for this disorder, answer the following: A. Assuming Hardy-Weinberg equilibrium, what percentage of people in the population would be expected to be heterozygous carriers

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Question:

The disorder known as cystic fibrosis (CF) is inherited in a recessive autosomal manner. In populations of Northern European descent, the frequency of people with CF is about 1 in 2,500. Assuming Hardy-Weinberg equilibrium for this disorder, answer the following: A. Assuming Hardy-Weinberg equilibrium, what percentage of people in the population would be expected to be heterozygous carriers

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Answer:The correct answer is - A. 3.9% people in the population would be expected to be heterozygous carriersExplanation:The genotype frequency for the CF affected is 1/2,500,= 1/2500= 0.004. This is equal to q^2here q = frequency of recessive alleles combination or CF people. (H-W equation => p^2+q^2+2pq=1)The allele frequency is the square root of q^2 value, which equals 0.02. The frequency of the dominant allele or p would be1 - 0.02 = 0.98 (p+q = 1) The frequency for the CF combinantion =0.004the dominant or unaffected people genotype = (098)^2 = 0.96; and for the heterozygote, it is = 2pq=2(0.98)(0.02) = 0.039 or 3.9%

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