Tanya has several bills in her wallet. She has a total of $40. If she has one more $5 bill than $10 bills, and two more $1 bills than $5 bills, how many of each does she have?

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Question:

Tanya has several bills in her wallet. She has a total of $40. If she has one more $5 bill than $10 bills, and two more $1 bills than $5 bills, how many of each does she have?

Answers

Answer: no. of $10 bill =2 no. of $5 bill = 3no. of $1 bill = 5Step-by-step explanation:Let the no. of $10 bill be xTotal value of $10 bill = $10*no. of $10 bill = $10xGiven that Tanya has one more $5 bill than $10 billsThus, no. of $5 bill = x+1Total value of $5 bill = $5*no. of $5 bill = $5(x+1)Also Given she has two more $1 bills than $5 billsno. of $1 bill = no. of $2 bill + 2 = x+1+2 = x+3Total value of $2 bill = $2*no. of $2 bill = $1(x+3).Therefore, total value of all the bill sin terms of x= 10x + 5(x+1) + 1(x+3)Given that she has total of $40,then10x + 5(x+1) + 1(x+3) = 4010x + 5x+5 + x+3 = 40=> 16x + 8 = 40=> 16x= 40-8=32=> x = 32/16= 2Thus, no. of $10 bill = x = 2 no. of $5 bill = x+1 = 2+1= 3no. of $1 bill = x+3 = 2+3=5

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