Suppose work input is 25 j and the output distance is 10 m factoring in the effect of friction which must be true about output force a) it equals 2.5n b) it is less than 2.5n c) it is greater than 2.5n
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Question:
suppose work input is 25 j and the output distance is 10 m factoring in the effect of friction which must be true about output force a) it equals 2.5n b) it is less than 2.5n c) it is greater than 2.5n
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Answer:Therefore F ∠ 2.5NExplanation:Definition of Work:It is the amount of energy transferred.Mathematical expression:W = F × dBy taking the friction into count it will define as:Input work = work against friction × output workNo we will put the values:25 J = w + 10 mj = kg m²/s²25 kg m²/s² = w + 10 mwhen friction is exist then w > 025 kg m²/s² - 10 m > 015 N > 0Therefore F ∠ 2.5N
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