Suppose that the material to be used in a fuse melts when the current density rises to 459 A/cm2. What diameter of cylindrical wire should be used to limit the current to 0.53 A?

2 answers
Question:

Suppose that the material to be used in a fuse melts when the current density rises to 459 A/cm2. What diameter of cylindrical wire should be used to limit the current to 0.53 A?

Answers

Answer: The required diameter of the fuse wire should be 0.0383 cm  to limit the current to 0.53 A with current density of 459 A/cm² .Explanation: We are given current density of 459 A/cm²  and we want to limit the current to 0.53 A in a fuse wire. We are asked to find the corresponding diameter of the fuse wire. Recall that current density is given byj = I/A where I is the current flowing through the wire and A is the area of the wire A = πr² but r = d/2  soA = π(d/2)² A = πd²/4 so the equation of current density becomes j = I/πd²/4 j = 4I/πd² Re-arrange the equation for dd² = 4I/jπ  d = √4I/jπ d = √(4*0.53)/(459π) d = 0.0383 cm Therefore, the required diameter of the fuse wire should be 0.0383 cm  to limit the current to 0.53 A with current density of 459 A/cm² .

Answer:diameter is 1 cmExplanation:diameter is 1 cm

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