Students ere investigating of a toy car. They performed 2 trials . Trial 1 / time(s) 5 , distance(m) 10, Trial 2 / Time(s) 20 distance(m) 40. What was the average speed of the toy car during the two trials

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Question:

Students ere investigating of a toy car. They performed 2 trials . Trial 1 / time(s) 5 , distance(m) 10, Trial 2 / Time(s) 20 distance(m) 40. What was the average speed of the toy car during the two trials

Answer: The average speed of the toy car during the two trials is 2m/s.Explanation:Speed can be defined as a type of scalar quantity in physics through which the rate at which an object travels through a distance is measured in a given amount of time. The formula for determining the speed of a car is:Speed= distance/ time which has an SI unit of m/s.From the speed tests carried out on a toy car, the speed of trial 1 is:Distance= 10 metersTime= 5 secondsTherefore trial one speed is 10/5= 2m/sWhile the speed of trial 2 is:Distance= 40metersTime= 20 secondsTherefore trial 2 speed is 40/ 20= 2mlsAverage speed of the toy car during the two trials is: Sum of both both speeds divided by total number of trials.Therefore: 2 m/s + 2m/s / 2= 2m/sFrom the calculation, the average speed of the toy car during the two trials is 2m/s.

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b.
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1
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