Sophia works in a clothing store and earns $40 per day. She earns an extra $5 for each outfit she sells. If Sophia wants to earn at least $70 per day, which inequality shows the minimum number of outfits, n, that she should sell? (5 points) 40 + 5n ≤ 70, so n ≤ 6 40 + 5n ≥ 70, so n ≥ 25 40 + 5n ≤ 70, so n ≤ 25 40 + 5n ≥ 70, so n ≥ 6

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Question:

Sophia works in a clothing store and earns $40 per day. She earns an extra $5 for each outfit she sells. If Sophia wants to earn at least $70 per day, which inequality shows the minimum number of outfits, n, that she should sell? (5 points) 40 + 5n ≤ 70, so n ≤ 6 40 + 5n ≥ 70, so n ≥ 25 40 + 5n ≤ 70, so n ≤ 25 40 + 5n ≥ 70, so n ≥ 6

Answers

Answer:In order to find this answer, you will need to be able to make an inequality. Step 1: Sophia makes $40 so start with that. 40 Step 2: Sophia also makes $5 per every outfit that she sells, so add that plus your variable (n). 40+5n Step 3: Determine if Sophia wants to make more, equal to or more, less, or less than or equal to than what she wants to make per day. 40+5n *draw a greater than or equal to sign. Step 4: Sophia wants to make more than or equal to what she makes per day. You will need to find what she wants to make more than. In this she wants to make more than or equal to $70. Equation: 40+5n *greater than or equal to sign* $70Step-by-step explanation:

Answer:   40 + 5n ≥ 70, so n ≥ 6Step-by-step explanation:   40 + 5n ≥ 70            5n ≥ 30               n ≥ 6

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