# Solving a value mixture problem using a system of linear... Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one same-day ticket is $55. For one performance, 35 advance tickets and 25 same-day tickets were sold. The total amount paid for the tickets was $1675. What was the price of each kind of ticket?

1 answer

###### Question:

Solving a value mixture problem using a system of linear...

Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one same-day ticket is $55. For

one performance, 35 advance tickets and 25 same-day tickets were sold. The total amount paid for the tickets was $1675. What was the price of each kind of

ticket?

Suppose that there are two types of tickets to a show: advance and same-day. The combined cost of one advance ticket and one same-day ticket is $55. For

one performance, 35 advance tickets and 25 same-day tickets were sold. The total amount paid for the tickets was $1675. What was the price of each kind of

ticket?

## Answers

Answer:Advance - $30Same day - $25Step-by-step explanation:Notice that if 35 advance and 25 same-day were sold, that means 25 "combos" and 10 advance tickets. 25 combos cost 25*$55=$1375That leaves $1675-$1375=$300 for the advance tickets.10 advance tickets cost $300, so 1 costs $300/10 = $30.That means a same-day ticket costs $55-$30=$25.Just to reverify:35*$30 + 25*$25 = $1675.

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