# Solve this linear equation for p: 2.6(5.5p – 12.4) = 127.92 1. Distributive property: 2. Addition property of equality: 3. Division property of equality: 4. Solution: 14.3p – 32.24 = 127.92 14.3p – 32.24 + 32.24 = 127.92 + 32.24 14.3p = 160.16 StartFraction 14.3 p Over 14.3 EndFraction equals StartFraction 160.16 Over 14.3 EndFraction.

2 answers

###### Question:

Solve this linear equation for p:

2.6(5.5p – 12.4) = 127.92

1. Distributive property:

2. Addition property of equality:

3. Division property of equality:

4. Solution:

14.3p – 32.24 = 127.92

14.3p – 32.24 + 32.24 = 127.92 + 32.24

14.3p = 160.16

StartFraction 14.3 p Over 14.3 EndFraction equals StartFraction 160.16 Over 14.3 EndFraction.

2.6(5.5p – 12.4) = 127.92

1. Distributive property:

2. Addition property of equality:

3. Division property of equality:

4. Solution:

14.3p – 32.24 = 127.92

14.3p – 32.24 + 32.24 = 127.92 + 32.24

14.3p = 160.16

StartFraction 14.3 p Over 14.3 EndFraction equals StartFraction 160.16 Over 14.3 EndFraction.

## Answers

Answer:[tex]2.6(5.5p - 12.4) = 127.92[/tex]• Distributive property[tex]14.3p - 32.24 = 127.92[/tex]• Addition property of equality[tex]14.3p = 127.92 + 32.24 \\ 14.3p = 160.16[/tex]• Division property of equality[tex] \frac{14.3p}{14.3} = \frac{160.16}{14.3} \\ \\ p = \frac{160.16}{14.3} [/tex]• Solution:[tex]{ \boxed{ \boxed{ \bf{ \: \: p = 11.2 \: \: }}}}[/tex]

Answer:11.2Step-by-step explanation:

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