Solve for x in the equation x2-8x+41=0

2 answers
Question:

Solve for x in the equation x2-8x+41=0

Answers

use the quadratic formula:-x = [-(-8) +/- sqrt((-8)^2 -4*41)] / 2  x =  ( 8 + sqrt (-100) / 2  and  (8 - sqrt(-100) / 2 =  4 + 5i , 4 - 5i     Answer

Answer:[tex]x=4{\pm}5i[/tex]Step-by-step explanation:The given equation is:[tex]x^2-8x+41=0[/tex]Since, the above equation cannot be easily factorized, thus using the discriminant method, we have[tex]x=\frac{-b{\pm}\sqrt{b^2-4ac}}{2a}[/tex][tex]x=\frac{-(-8)\pm\sqrt{(-8)^2-4(1)(41)}}{2}[/tex][tex]x=\frac{8{\pm}\sqrt{64-164}}{2}[/tex][tex]x=\frac{8\pm\sqrt{-100}}{2}[/tex][tex]x=\frac{8\pm10i}{2}[/tex][tex]x=4{\pm}5i[/tex]Thus, the values of x are: [tex]4+5i and 4-5i[/tex].

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