Shortly after a vinyl record (radius 0.152 m) starts rotating on a turntable, its angular velocity is 1.60 rad/s and increasing at a rate of 8.00 rad/s2. At this instant, for a point at the rim of the record, what is the tangential component of acceleration

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Question:

Shortly after a vinyl record (radius 0.152 m) starts rotating on a turntable, its angular velocity is 1.60 rad/s and increasing at a rate of 8.00 rad/s2. At this instant, for a point at the rim of the record, what is the tangential component of acceleration

Answers

Answer:The tangential component of acceleration is 1.216 [tex]\frac{m}{s^{2} }[/tex]Explanation:Given:Radius of turntable [tex]r = 0.152[/tex] mAngular velocity [tex]\omega = 1.60[/tex] [tex]\frac{rad}{s}[/tex]Angular acceleration [tex]\alpha = 8[/tex] [tex]\frac{rad}{s^{2} }[/tex]For finding tangential component of acceleration,We use rotational mechanics,Tangential acceleration is given by,   [tex]a_{tan} = \alpha r[/tex]Where [tex]\alpha =[/tex] angular acceleration, [tex]r =[/tex] radius of turntable   [tex]a_{tan} = 8 \times 0.152[/tex]   [tex]a_{tan} = 1.216[/tex] [tex]\frac{m}{s^{2} }[/tex]Therefore, the tangential component of acceleration is 1.216 [tex]\frac{m}{s^{2} }[/tex]

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