# Seth is using the figure shown below to prove Pythagorean Theorem using triangle similarity: In the given triangle ABC, angle A is 90° and segment AD is perpendicular to segment BC. The figure shows triangle ABC with right angle at A and segment AD. Point D is on side BC. Which of these could be a step to prove that BC2 = AB2 + AC2? (6 points) By the cross product property, AB2 = BC multiplied by BD. By the cross product property, AC2 = BC multiplied by BD. By the cross product property, AC2 = B

1 answer

###### Question:

Seth is using the figure shown below to prove Pythagorean Theorem using triangle similarity:

In the given triangle ABC, angle A is 90° and segment AD is perpendicular to segment BC.

The figure shows triangle ABC with right angle at A and segment AD. Point D is on side BC.

Which of these could be a step to prove that BC2 = AB2 + AC2? (6 points)

By the cross product property, AB2 = BC multiplied by BD.

By the cross product property, AC2 = BC multiplied by BD.

By the cross product property, AC2 = BC multiplied by AD.

By the cross product property, AB2 = BC multiplied by AD.

In the given triangle ABC, angle A is 90° and segment AD is perpendicular to segment BC.

The figure shows triangle ABC with right angle at A and segment AD. Point D is on side BC.

Which of these could be a step to prove that BC2 = AB2 + AC2? (6 points)

By the cross product property, AB2 = BC multiplied by BD.

By the cross product property, AC2 = BC multiplied by BD.

By the cross product property, AC2 = BC multiplied by AD.

By the cross product property, AB2 = BC multiplied by AD.

## Answers

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