Sarah is running a race and is almost to the finish line. In the last 5 seconds, her velocity changes from 2m/s to 4m/s. What is her average acceleration during the last 5 seconds of the race?

2 answers
Question:

Sarah is running a race and is almost to the finish line. In the last 5 seconds, her velocity changes from 2m/s to 4m/s. What is her average acceleration during the last 5 seconds of the race?

Answers

Answer:[tex]\boxed {\boxed {\sf a= \frac {2}{5} \ or \ 0.4 \ m/s^2}}[/tex]Explanation:Acceleration is found by dividing the change in velocity by the time. The formula is: [tex]a= \frac {v_f-v_i}{t}[/tex]where [tex]v_f[/tex] is the final velocity, [tex]v_i[/tex] is the initial or starting velocity, and [tex]t[/tex] is the time. Her velocity changes from 2 meters per second to 4 meters per second in the 5 seconds. Therefore: [tex]v_f= 4 \ m/s \\v_i= 2 \ m/s \\t=5 \ s[/tex]Substitute the values into the formula. [tex]a= \frac { 4 \ m/s- 2 \ m/s}{5 \ s}[/tex]Solve the numerator and subtract. [tex]a= \frac { 2 \ m/s}{5 \ s}[/tex]Divide. [tex]a= \frac{2}{5} \ m/s/s= \frac{2}{5} \ m/s^2[/tex]This can also be written as a decimal.[tex]a=0.4 \ m/s^2[/tex]Her average acceleration during the last 5 seconds of the race is 2/5 or 0.4 meters per square second.

Answer:Solution :-HereInitial velocity = 2 m/sFinal velocity = 4 m/sTime = 5 secv = u + at4 = 2 + a(5)4 - 2 = a(5)2 = 5a2/5 = aHence, acceleration is 2/5 m/s²

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