S is the midpoint of RT. If RS = 4x - 3 and RT = 6x - 4, what’s the value of ST?
1 answer
Question:
S is the midpoint of RT.
If RS = 4x - 3 and RT = 6x - 4,
what’s the value of ST?
If RS = 4x - 3 and RT = 6x - 4,
what’s the value of ST?
Answers
Answer:R__S__TRT = RS + ST6x – 4 = ( 4x – 3) + ST(6x – 4 ) – ( 4x – 3 ) = ST(6x – 4 ) +( – 4x + 3 ) = ST2x – 1 = STST = 2x – 1RS=ST4x – 3 = 2x – 14x – 2x = – 1 +32x = 2x= 2/2x =1ST = 2x – 1 = 2(1) – 1 =2 ‐ 1 = 1ST = 1I hope I helped you^_^
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