# Plzzzzz help due tomorrow

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## Answers

Answer:Q1 m² +10m+ 21 Q2a) 3 (2 +3x) b) (y+4) (y-4) c) (2p-5) (p+2) Step-by-step explanation:Q1. expand and simplify (m+7)(m+3) solution (m+7)(m+3) m² + 7m+ 3m + 21 m² +10m+ 21 Q2 Factorize a) 6 +9x Answer Taking 3 common 3 (2 +3x) b) y² -16 answer y² -4 as formula a² –b² = (a+b)(a-b) (y+4) (y-4) c) 2p² –p-10 So according to quadratic equation a=2 b=-1 c=-10 a x c =-20 b=-1 we need two number whose product is -20 and sum is -1 -5 x 4 = -20 -5 +4 = -1 2p² –p-10 = 2p² + 4p-5p-10 =2p (p +2) -5 (p+2) = (2p-5) (p+2) please mark me brainliest :D

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