PLEASE HELP! (don't graph, give me the coordinates and i will graph myself)
2 answers
Question:
PLEASE HELP! (don't graph, give me the coordinates and i will graph myself)
Answers
9514 1404 393Answer: see below for a tableStep-by-step explanation:You can easily identify intercept points by solving for one variable when the other is zero.x-intercept (y=0) 4x = 12 x = 12/4 = 3y-intercept (x=0) -3y = 12 y = 12/-3 = -4So, the coordinate pairs of these points are ... (3, 0) and (0, -4)__If you solve for y, you get ... -3y = 12 -4x y = (4/3)x -4 . . . . . divide by -3This suggests that x being a multiple of 3 will be useful for finding integer values of y.We already have points for x=0 and x=3. We can add points for x=6 and x=-3. y = 4/3(6) -4 = 4 y = 4/3(-3) -4 = -8So, the additional points are ... (6, 4) and (-3, -8)
Answer:X=3y= -4Step-by-step explanation:If we're solving for x or y, then the intercept we're not solving for is equal to zero. Solving for y means x=0, solving for x means y=0. so solving for x, 4x=12--> x=3, since y=0 in this scenario. Solving for y, x=0, so -3y=12--> y=(-4)
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