# PLEASE HELP ASAP! Write the equation in standard form for the circle with radius √43 and center (4, − 7).

1 answer

###### Question:

PLEASE HELP ASAP!

Write the equation in standard form for the circle with radius √43 and center (4, − 7).

Write the equation in standard form for the circle with radius √43 and center (4, − 7).

## Answers

Answer:[tex](x-4)^2+(y+7)^2=43[/tex]Step-by-step explanation:The standard equation of a circle is given by: [tex](x-h)^2+(y-k)^2=r^2[/tex]Where (h, k) is the center and r is the radius. We are given that the center is (4, -7) and that the radius is √(43). So, h = 4, k = -7, and r = √(43). Substitute: [tex](x-(4))^2+(y-(-7))^2=(\sqrt{43})^2[/tex]Simplify. Hence, our equation is: [tex](x-4)^2+(y+7)^2=43[/tex]

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