PLEASE HELP, 30 POINTS!Suppose 1 kg each of water (4.19 J/g⋅∘C), brick (0.90 J/g⋅∘C), iron (0.46 J/g⋅∘C), and plastic (1.01 J/g⋅∘C) were held at the same initial temperature and heated for an equivalent amount of time. Indicate the relative final temperatures by ordering from lowest to highest resulting temperature (if using the Intro tab of the PhET to help visualize the temperature changes, assume the water iron, and plastic are 1 kg in mass, and the brick has a mass of 0.5 kg). Assume no heat

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Question:

PLEASE HELP, 30 POINTS!
Suppose 1 kg each of water (4.19 J/g⋅∘C), brick (0.90 J/g⋅∘C), iron (0.46 J/g⋅∘C), and plastic (1.01 J/g⋅∘C) were held at the same initial temperature and heated for an equivalent amount of time. Indicate the relative final temperatures by ordering from lowest to highest resulting temperature (if using the Intro tab of the PhET to help visualize the temperature changes, assume the water iron, and plastic are 1 kg in mass, and the brick has a mass of 0.5 kg). Assume no heat is lost to the surroundings.
Rank from lowest resulting temperature to highest resulting temperature. To rank items as equivalent, ove

Answers

Scenario 1:Mass of  each of water, brick, iron, and plastic = 1 kg = 1000 gSpecific heat of water = 4.19 J/g⋅∘CTo raise the temperature of  1 g of water by 1∘C the heat required is 4.19 JTherefore, to raise the temperature of  1000 g of water by 1∘C the heat required is 4.19  x 1000 = 4190 JSpecific heat of brick =  0.90 J/g⋅∘CTo raise the temperature of  1 g of brick by 1∘C the heat required is 0.9JTherefore, to raise the temperature of 1000 g of brick by 1∘C the heat required is 0.90  x 1000 = 900 JSpecific heat of iron = 0.46 J/g⋅∘CTo raise the temperature of  1 g of iron by 1∘C the heat required is 0.46 JTherefore, to raise the temperature of  1000 g of iron by 1∘C the heat required is 0.46  x 1000 = 460 JSpecific heat of plastic = 1.01 J/g⋅∘CTo raise the temperature of  1 g of plastic by 1∘C the heat required is 1.01 JTherefore, to raise the temperature of  1000 g of plastic by 1∘C the heat required is 1.01  x 1000 = 1010 JSo it takes the greatest amount of heat in Joules to raise the temperature of water, followed by plastic, followed by brick and iron. Now all of them are heated for an equivalent amount of time as a result water will have the lowest resulting or final temperature. The resulting or final temperature of plastic will be greater than water. The resulting or final temperature of brick will be greater than plastic. . The resulting or final temperature of iron will be greater than brick. Water                   plastic    brick    iron (lowest resulting temperature) -->  (highest resulting temperature)

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