In this right triangle LMN L and M are complentary angles and sin (L) is 19\20 what is cos (M)

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Question:

in this right triangle LMN L and M are complentary angles and sin (L) is 19\20 what is cos (M)

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In any right triangle ABC, with right angle A we have the following:[tex]\sin(\angle B)=\cos(\angle C)[/tex]and[tex]\sin(\angle C)=\cos(\angle B)[/tex].This means that the sine of a non 90° angle, is equal to the cosine of its complementary angle.Thus, [tex]\displaystyle{ \cos(\angle M)=\sin (\angle L)= \frac{19}{20} [/tex].(Take a look at the picture. From the definition of trigonometric ratios in right triangles we have :[tex]\displaystyle { \sin(\angle L)= \frac{opposite \ side}{hypotenuse} = \frac{19}{20}. [/tex]and [tex]\displaystyle { \cos(\angle M)= \frac{adjacent \ side}{hypotenuse} = \frac{19}{20}. [/tex])Answer: 19/20

Answer:19/20Step-by-step explanation:

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