In a certain Algebra 2 class of 27 students, 11 of them play basketball and 9 of them play baseball. There are 11 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?
1 answer
Question:
In a certain Algebra 2 class of 27 students, 11 of them play basketball and 9 of them play baseball. There are 11 students who play neither sport. What is the probability that a student chosen randomly from the class plays both basketball and baseball?
Answers
Answer:The probability of students who play both basketball and baseball = [tex]\frac{4}{27}[/tex]Step-by-step explanation:In a certain Algebra class,The total number of students = 27 studentsLet the students playing basketball be represented as A and baseball as B.The students who play basketball, A= 11 The students who play basetball,B =9 The students who play neither sport, = 11 The students who play both basketball and baseball, = ?By formula, P(AUB)=P(A)+P(B)-P(A∩B)Substituting the values in the equation, we get P(AUB) = [tex]\frac{11}{27} + \frac{9}{27} - \frac{16}{27}[/tex] P(AUB) = [tex]\frac{4}{27}[/tex]The probability of students who play both basketball and baseball = [tex]\frac{4}{27}[/tex]
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