If you want to prepare 0.50 liters of a 0.35 M solution of NaNO3, how many grams of the salt should you weigh out?

1 answer
Question:

If you want to prepare 0.50 liters of a 0.35 M solution of NaNO3, how many grams of the salt should
you weigh out?

Answers

Answer:14.87 g Explanation:Molarity refers to the concentration of a solution in moles per liter.It is calculated by dividing the number of moles of solute and the volume of the solution.We are given;Volume as 0.5 liters Molarity as 0.35 M We are required to calculate the mass of the solute NaNO₃Step 1 : Find the number of moles of the solute NaNO₃Moles = Molarity × Volume Moles = 0.35 M × 0.5 L          = 0.175 moles Step 2: Mass of the solute NaNO₃Mass is calculated by multiplying the number of moles by the molar mass of the compound.Molar mass of NaNO₃ = 84.9947 g/molTherefore;Mass of NaNO₃ = 0.175 moles × 84.9947 g/mol                           = 14.874 g                          = 14.87 g Thus, the mass of the salt solute is 14.87 g

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