If the magnitude of a positive charge is tripled, what is the ratio of the original value of the electric field at a point to the new value of the electric field at that same point? a) 1:2 b) 1:3 c) 1:6 d) 1:9
1 answer
Question:
If the magnitude of a positive charge is tripled, what is the ratio of the original value of the electric field at a point to the new value of the electric field at that same point?
a) 1:2
b) 1:3
c) 1:6
d) 1:9
a) 1:2
b) 1:3
c) 1:6
d) 1:9
Answers
Answer: b)1 :3Explanation:Lets thatThe value of a positive charge = qAs we know that electric filed on a point charge given as[tex]E=\dfrac{Kq}{r^2}[/tex]Where ,K=Constantq=Charge ,r=DistanceIf the value of the charge gets tripled ,q'= 3 qThen electric filed E'[tex]E'=\dfrac{Kq'}{r^2}[/tex][tex]E'=\dfrac{3Kq}{r^2}[/tex]E' = 3 ETherefore we can say that[tex]\dfrac{E}{E'}==\dfrac{1}{3}[/tex]therefore the answer will be -- b)1 :3
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