If square A has a side of length 5 inches, how many times bigger is the area of square B if it has a side of length 25 inches?

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Question:

If square A has a side of length 5 inches, how many times bigger is the area of square B if it has a side of length 25 inches?

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Answer:24 timesStep-by-step explanation:It is given that :The length of the side of square A = 5 inchesThe length of the side of square B = 25 inchesTherefore, area of square A = 5 x 5                                                = 25 square inchesSimilarly, area of square B = 25 x 25                                             = 625 square inchesTherefore, number of times the square B is bigger than the square A is given by :[tex]$=\frac{625-25}{25}$[/tex][tex]$=\frac{600}{25}$[/tex]= 24 Thus the square B is 24 times bigger than square A

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