If 2a+3b=12 and ab=6 find the value of 8a^3+27b^3

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Question:

If 2a+3b=12 and ab=6 find the value of 8a^3+27b^3

Answers

A) 2a + 3b = 12B) ab = 6 solving for aB) a = 6 / b then we substitute this into equation A)A) 12 / b + 3b = 12  multiplying this by "b"A) 12 + 3b^2 = 12bA) 3b^2 -12b +12= 0 dividing by "3"A) b^2 -4b + 4 = 0Factoring(b-2) * (b-2) = 0b = 2Since b = 2 then a = 3NOW, we put these numbers into:8a^3 +27b^3 8*3*3*3 + 27*2*2*2216 + 216The answer is 512

a b = 6a = 6/b2 *6/b + 3b = 1212/b + 3b = 1212 + 3b^2 = 12b3b^2 - 12b + 12 = 0b^2 - 4b +4 = 0(b -  2)^2 = 0b = 2a will = 38*3^3 + 27*2^38*27 + 27*8I'm getting 432I thought perhaps I could do this a shorter way. Turns out I can't. If you give out a Brainly Please give it to the other responder.

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