# I would really appreciate the help :[ Will mark Brainliest, 98 points. What is the area of a parallelogram whose vertices are E(−9, -2), F(9, -2), G(1, −7), and H(-17, −7)? Enter your answer in the box.

2 answers

###### Question:

I would really appreciate the help :[

Will mark Brainliest, 98 points.

What is the area of a parallelogram whose vertices are E(−9, -2), F(9, -2), G(1, −7), and H(-17, −7)?

Enter your answer in the box.

Will mark Brainliest, 98 points.

What is the area of a parallelogram whose vertices are E(−9, -2), F(9, -2), G(1, −7), and H(-17, −7)?

Enter your answer in the box.

## Answers

Answer:A = 90Step-by-step explanation:We need to find the length of the baseLet EF be the baselength = change in x (since the y's are the same value) = (9--9) = (9+9) = 18Now we need to find the height (change in y values)-7 --2-7 +2 = -5But the value is positive because we are finding the distance height is 5 unitsA = bhA = 18*5A = 90

Answer:90Step-by-step explanation: = (9--9)= 18 bc remember when there is two negatives together it becomes a positive.-7+2 = -5A = bh now since our b is 18 and our h is 5 were going to multiply themA = 18*5A = 90~batmans wife dun dun dun....

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