How many solutions for x does the following equation have? 4/5(20x + 5) = 16x - 2 A. 1 B. -2 C. 0 D. infinite

2 answers
Question:

How many
solutions for x does the following equation have?
4/5(20x + 5) = 16x - 2
A. 1
B. -2
C. 0
D. infinite

Answers

Answer:There are no solutionsStep-by-step explanation:4/5 ( 20x + 5 ) = 16x - 2Distibute on the left:( 4/5 x 20 x ) + ( 4/5 x 5 ) = 16x - 216x + 4 = 16x - 2Subtract 16x from both sides:4=-2Add 2 to each side:6=0No solutions

the answer will be c zero

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