How many moles of MgSiO3 are in 203 g of the compound?

2 answers
Question:

How many moles of MgSiO3 are in 203 g of the compound?

Answers

molar mass MgSiO3 =  100.38 g/mol1 mole MgSiO3 ------------ 100.38 g?? moles MgSiO3 ---------- 203 g203 x 1 / 100.38 => 2.0223 moles

Answer: The number of moles of [tex]MgSiO_3[/tex] is 2.02 moles.Explanation:To calculate the number of moles, we use the equation:[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]     We are given:Given mass of [tex]MgSiO_3[/tex] = 203 gMolar mass of [tex]MgSiO_3[/tex] = 100.4 g/molPutting values in above equation, we get:[tex]\text{Moles of }MgSiO_3=\frac{203g}{100.4g/mol}=2.02mol[/tex]Hence, the number of moles of [tex]MgSiO_3[/tex] is 2.02 moles.

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