How many moles of mercury atoms are in 5.418 x 1023 atoms of mercury? moles

2 answers
Question:

How many moles of mercury atoms are in 5.418 x 1023 atoms of mercury? moles

Answers

Answer:0.9 moles of Hg contain 5.418×10²³ atomsExplanation:As we know, Avogadro's number (NA) is the amount of particles that are contained in 1 mol → 6.02×10²³Let's make a rule of three for this:6.02×10²³ atoms are contained in 1 mol of Hg5.418×10²³ atoms would be contained in (5.418×10²³ . 1) / NA = 0.9 moles

Answer:We have 0.8997 moles of mercury in 5.418 * 10^23 atoms of mercuryExplanation:Step 1: Data givenNumber of atoms of mercury = 5.418 * 10^23 atomsNumber of Avogadro = 6.022 *10^23 /molStep 2: Calculate number of moles of mercuryMoles mercury = number of atoms mercury / number of AvogadroMoles mercury = 5.418 *10^23 /6.022*10^23 /molMoles mercury = 0.8997 moles We have 0.8997 moles of mercury in 5.418 * 10^23 atoms of mercury

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