How many atoms of H are in 93.2 grams of PH3?

2 answers
Question:

how many atoms of H are in 93.2 grams of PH3?

Answers

Answer:Explanation:One way to approach this problem is to determine the percent composition of hydrogen in water.You know that one water molecule containsone oxygen atomtwo hydrogen atomsThis means that every mole of water molecules will contain 2 moles of hydrogen and 1 mole of oxygen atoms.To find the percent composition of hydrogen in water, use the molar mass of water and that of hydrogen2×1.00794g/mol18.0153g/mol×100=11.19%This means that every 100 g of water will contain a total of 11.19 g of hydrogen. Since your sample has a mass of 23.5 g, it follows that it will contain23.5g water⋅11.19 g H100g water=2.63 g HAlternatively, you can first find the number of moles of water in get in that 23.5 g sample23.5g⋅1 mole H2O18.0153g=1.3044 moles H2OSInce one molecule of water contais 2 atoms of hydrogen, you will get1.3044moles water⋅2 moles H1mole water=2.6088 moles HFinally, use hydrogen's molar mass to find how many grams would contain this many moles2.6088moles⋅1.00794 g H1mole=2.63 gExplanation:

Answer: 2.63Explanation:One way to approach this problem is to determine the percent composition of hydrogen in water.

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