How is X squared plus 4X -8 equals zero

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Question:

how is X squared plus 4X -8 equals zero

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x^2 + 4x - 8 = 0Move constant to right side.x^2 + 4x = 8Let's complete the square to find x. (4/2)^2 = 4We add 4 to both sides.x^2 + 4x + 4 = 8 + 4Factor left side.(x + 2)(x + 2) = 12(x + 2)^2 = 12Take square root on both sides.sqrt{(x + 2)^2} = sqrt{12}x + 2 = 2•sqrt{3}x + 2 = -2•sqrt{3}Two answers:x = - 2 + 2•sqrt{3}Andx = -2 - 2•sqrt{3}

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