How do you write the vertex form equation of the parabola #y=2x^2 +11x-6#?

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Question:

How do you write the vertex form equation of the parabola #y=2x^2 +11x-6#?

Answers

The easist way to find the vertex is to complete the square:y=2x^2 +11x-6  =>  y=2[ x^2 + (11/2)x  + (11/2)^2   - (11/2)^2 ]  - 6  This can be rewritten as                                 y = 2[(x+11/2)^2 ] -(121/4) - 24/4                                y = 2 (x+11/2)^2 - 145/4this is the equation in vertex form.  The vertex is at (-11/2, -145/4).

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