Hi Jose, when you submit this form, the owner will be able to see your name and email address. 1. A 100. g samle of water absorbs how many Joules of energy as its temperature is changed from 35.0 C to 60.0 C. (water s = 4.184 J/g C)

1 answer
Question:

Hi Jose, when you submit this form, the owner will be able to see your name and email address.
1. A 100. g samle of water absorbs how many Joules of energy as its temperature is changed from
35.0 C to 60.0 C. (water s = 4.184 J/g C)

Answers

Answer: 10460JExplanation:Given parameters: Mass of water sample  = 100g Initial temperature = 35°C Final temperature  = 60°C Unknown: Amount of energy absorbed by water = ? Solution: The amount of energy absorbed by water is mathematically expressed below;     H  = m C ΔT H is the amount of energy m is the mass C is the specific heat capacity of water  = 4.184J/g°C ΔT  = 60°C  - 35°C  = 25°C  Now insert the parameters and solve;  H = 100 x 4.184 x 25  = 10460J

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