Help its geometry...............

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Question:

Help its geometry...............

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m GH = 57''________tan 39° = opposite / adjacenttan 39° = m GH / m HJtan 39° *  m HJ = m GHm HJ = m GH / tan 39°m HJ ≈ 57'' / 0.810m HJ ≈ 70.4''    <———    measure of the segment HJ________sin 39° = opposite / hypotenusesin 39° = m GH / m GJsin 39° * m GJ = m GHm GJ = m GH / sin 39°m GJ = 57'' / 0.629m GJ ≈ 90.6''    <———    measure of the segment GJ________So the perimeter isp  =  m GH  +  m HJ  +  m GJp  =  57''  +  70.4''  +  90.6''p  =  218''    <———    this is the answer.I hope this helps. =)Tags:  perimeter right triangle sine cosine tangent sin cos tan trig trigonometry geometry

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