Given: cosθ= -4/5 , sin x = -12/13 , θ is in the third quadrant, and x is in the fourth quadrant; evaluate tan 1/2 θanswer choices:A. -3B. 3C. 1/3
1 answer
Question:
Given: cosθ= -4/5 , sin x = -12/13 , θ is in the third quadrant, and x is in the fourth quadrant; evaluate tan 1/2 θ
answer choices:
A. -3
B. 3
C. 1/3
answer choices:
A. -3
B. 3
C. 1/3
Answers
Answer:Step-by-step explanation:If you're looking for what the half angle of the tangent of theta is, I'm a bit confused as to why you think the angle in the 4th quadrant, x, is relevant. But maybe you don't know it isn't and it's a "trick" to throw you off. Hmm... Anyways, the half angle identity for tangent is[tex]tan(\frac{\theta}{2})=\frac{sin\theta}{1+cos\theta}[/tex]There are actually 3 identities for the tangent of a half angle, but this one works just as well as either of the others do, so I'm going with this one. If theta is in QIII, the value of -4 goes along the x axis and the hypotenuse is 5. That makes the missing side, by Pythagorean's Theorem, -3. Filling in our formula:[tex]tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{1+(-\frac{4}{5}) }[/tex] which simplifies a bit to[tex]tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{\frac{5}{5} -\frac{4}{5} }[/tex] and a bit more to[tex]tan(\frac{\theta}{2})=\frac{-\frac{3}{5} }{\frac{1}{5} }[/tex]Bring up the lower fraction and flip it to divide to get[tex]tan(\frac{\theta}{2})=-\frac{3}{5}*\frac{5}{1}[/tex] which of course simplifies to -3. Choice A.
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