G A 320-g air track cart is traveling at 1.25 m/s and a 270-g cart traveling in the opposite direction at 1.33 m/s. What is the speed of the center of mass of the two carts

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Question:

g A 320-g air track cart is traveling at 1.25 m/s and a 270-g cart traveling in the opposite direction at 1.33 m/s. What is the speed of the center of mass of the two carts

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Answer:1.287m/sExplanation:Using the law of conservation of mass expressed as;m1u1+m2u2 = (m1+m2)vm1 and m2 are the masses of the objectsu1 and u2 are the velocitiesv is the speed of the center of mas of the two cartsGivenm1 = 320g = 0.32kgu1 = 1.25m/sm2 = 270g = 0.27kgu2 = 1.33m/sSubstitute this value into the formula and get v;0.32(1.25)+0.27(1.33) =  (0.32+0.27)v0.4+0.3591 = 0.59v0.7591 = 0.59vv = 0.7591/0.59v = 1.287m/shence the speed of the center of mass of the two carts is 1.287m/s

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