Friction: During a hockey game, a puck is given an initial speed of 10 m/s. It slides 50 m on the horizontal ice before it stops due to friction. What is the coefficient of kinetic friction between the puck and the ice

Answer:The  value is  [tex]\mu_k = 0.102 0[/tex]Explanation:From the question we are told that     The initial speed is  [tex]u = 10 \ m/s[/tex]     The  distance traveled is  [tex]d = 50 \ m[/tex]  Generally we can obtain the acceleration using the kinetic equation as follows      [tex]v^2 = u^2 + 2as[/tex]=>   [tex]a = \frac{v^2 - u^2 }{ 2s}[/tex]=>   [tex]a = \frac{0^2 - 10^2 }{ 2 * 50 }[/tex]=>   [tex]a = -1 m/s^2[/tex]The  negative sign shows that the pluck is decelerating   The force driving the pluck is mathematically evaluated as        [tex]F = ma[/tex]  This force is also equivalent to the frictional force acting on the pluck So         [tex]ma = m * g* \mu_k[/tex]=>  [tex]\mu_k = \frac{a}{g}[/tex]=>   [tex]\mu_k = \frac{1}{9.8 }[/tex]=>   [tex]\mu_k = 0.102 0[/tex]