Find the x- and y intercepts for the linear equation 4. 3x + 2y = 6 5. 4x – 9y = 36 6. x + y = -3 8. Xx - 3y = 12

1 answer
Question:


Find the x- and y intercepts for the linear equation
4. 3x + 2y = 6
5. 4x – 9y = 36
6. x + y = -3
8. Xx - 3y = 12

Answers

4. 3x + 2y = 6x-intercept = 2 ,  y - intercept = 35. 4x – 9y = 36x-intercept = 9, y - intercept = -46. x + y = -3x-intercept = -3, y - intercept = -38. x - 3y = 12x-intercept = 12, y - intercept = -4Step-by-step explanation:To find the x-intercept we put y=0 in the equation and to find the y-intercept we put x = 0 in the equation4. 3x + 2y = 6Putting y = 0 [tex]3x + 2y = 6\\3x +2(0) = 6\\3x = 6\\\frac{3x}{3} = \frac{6}{3}\\x= 2[/tex]Putting x=0[tex]3x + 2y = 6\\3(0) + 2y = 6\\2y = 6\\\frac{2y}{2} = \frac{6}{2}\\y= 3[/tex]5. 4x – 9y = 36Putting y = 0 [tex]4x -9y = 36\\4x - 9(0) = 36\\4x = 36\\\frac{4x}{4} = \frac{36}{4}\\x = 9[/tex]Putting x=0[tex]4(0) -9y = 36\\-9y=36\\\frac{-9x}{-9} = \frac{36}{-9}\\x =-4[/tex]6. x + y = -3Putting y = 0 [tex]x+y=-3\\x+0 = -3\\x = -3[/tex]Putting x=0[tex]x + y = -3\\0+y=-3\\y=-3[/tex]8. X - 3y = 12Putting y=0[tex]x - 3(0) = 12\\x -0 = 12\\x = 12[/tex]Putting x = 0[tex]0-3y = 12\\-3y = 12\\\frac{-3y}{-3} =\frac{12}{-3}\\y=-4[/tex]Keywords: Linear equationLearn more about linear equations at:brainly.com/question/2150928brainly.com/question/2154850#LearnwithBrainly

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