Find the vertical asymptote for y=x^2-5x/x^2-x-2
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Answer:vertical asymptote at x=2 and x=-1Step-by-step explanation:[tex]y= \frac{x^2-5x}{x^2-x-2}[/tex]To find out vertical asymptote we set the denominator =0 and solve for x[tex]x^2 - x - 2=0[/tex]now factor left hand sidefind out two factors whose product is -2 and sum is -1-2 times 1 = -2-2+1 = -1(x-2)(x+1) =0x-2 =0 so x= 2x+1 =0 so x=-1vertical asymptote at x=2 and x=-1
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