Find the 24th term of an arithmetic sequence for which a_1 = 2 and d = 6.

2 answers
Question:

Find the 24th term of an arithmetic sequence for which a_1 = 2 and d = 6.

Answers

Answer:140Step-by-step explanation:The n th term of an arithmetic sequence is[tex]a_{n}[/tex] = a₁ + (n - 1)dwhere a₁ is the first term and d the common differenceHere a₁ = 2 and d = 6 , thus[tex]a_{24}[/tex] = 2 + (23 × 6) = 2 + 138 = 140

Answer:  a₂₄ = 140Step-by-step explanation:The formula for an arithmetic sequence is: [tex]a_n=a_1+d(n-1)[/tex]  wherea₁ is the first term of the sequenced is the difference between termsn is the term you are looking forGiven: a₁ = 2, d = 6, n = 24a₂₄ = 2 + 6(24 - 1)      = 2 + 6(23)      = 2  + 138     = 140The 24th term is 140.

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