Find an equation of a plane making an angle of pi/2 with the plane -3x-y+4z=-2
1 answer
Question:
Find an equation of a plane making an angle of pi/2 with the plane -3x-y+4z=-2
Answers
you just need a vector that is perpendicular to the normal vector for your plane. Your normal is <3, 1, -4>. An orthogonal vector is<4, 0, 3>The plane through the origin with this as it's normal is4x + 3z = 0
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