Find an equation for line perpendicular to 2x+6y=18 and goes through the point (8,-1)

2 answers
Question:

Find an equation for line perpendicular to 2x+6y=18 and goes through the point (8,-1)

Answers

Answer:3x +y = -2Step-by-step explanation:First of all, it is helpful to put the given equation in standard form. We can do that by dividing it by 2 to eliminate the common factor from the numbers.  x -3y = 5 Next, since you want the perpendicular line, you can swap the coefficients of x and y, and negate one of them. This can give you ...  3x +y = (some constant) The constant will be found using the given point.  3x +y = 3(2) +(-8) = -2 . . . the perpendicular line An equation is ...  3x +y = -2

Answer:y = 3x - 25Step-by-step explanation:The equation of a line in slope- intercept form isy = mx + c ( m is the slope and c the y- intercept )Given2x + 6y = 18 ( subtract 2x from both sides )6y = - 2x + 18 ( divide terms by 6 )y = - [tex]\frac{1}{3}[/tex] x + 3 ← in slope- intercept formwith slope m = - [tex]\frac{1}{3}[/tex]Given a line with slope m then the slope of a line perpendicular to it is[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{-\frac{1}{3} }[/tex] = 3 , theny = 3x + c ← is the partial equationTo find c substitute (8, - 1 ) into the partial equation- 1 = 24 + c ⇒ c = - 1 - 24 = - 25y = 3x - 25 ← equation of perpendicular line

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