Consider a vector G pointed 36.9 degrees clockwise from the positive y-axis. The vector's x- component has a value of 3. Find the magnitude of vector G. ​

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Question:

Consider a vector G pointed 36.9 degrees clockwise from the positive y-axis. The vector's x- component has a value of 3. Find the magnitude of vector G. ​

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A vector quantity has both magnitude and direction, and therefore, can be resolved into componentsThe magnitude of the vector, G is approximately 5 unitsThe value of the magnitude of the vector is correct for the following reason:The given parameters are;The direction in which the vector, G, is pointed, θ = 36.9° clockwise rotation from the positive y-axisThe x-component of the vector = 3Required:To find the magnitude of the vectorSolution:Let |G|, represent the magnitude of the vectorGiven that the angle, is measured from the y-axis, we have;|G| × sin(θ) = The x-component of the vectorTherefore;|G| × sin(36.9°) = 3[tex]|G| = \dfrac{3}{sin(36.9^{\circ})} \approx 4.9965 \approx 5[/tex]The magnitude of the vector, G ≈ 5Learn more about vector components here:https://brainly.com/question/3411372

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