As a block of ice melts, its weight changes from 1 3/4 lb to 1/4 lb. This change takes 1/4 h. The ice melts at a constant rate. At what rate does the weight of the ice change? Show your work. pleaseeeeee help =)

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Question:

As a block of ice melts, its weight changes from 1 3/4 lb to 1/4 lb. This change takes 1/4 h. The ice melts at a constant rate. At what rate does the weight of the ice change? Show your work.
pleaseeeeee help =)

Answers

Question:-As a block of ice melts, its weight changes from 1 3/4 lb to 1/4 lb. This change takes 1/4 h. The ice melts at a constant rate. At what rate does the weight of the ice change?Answer:-You should have these values backwards like:-=>  1/34 lb is less than 1/4 lb. Next:-We're gonna find a specific common denominator, Then we get: (17/68 - 2/68)/(1/4) = 60/68 = 15/17 lb/hour___________________________

[tex]\huge{ \mathfrak{ \underline{ Answer}}} \: \: ✓ [/tex]____________________________Change in weight :[tex]1 \dfrac{3}{4} - \dfrac{1}{4} [/tex][tex] \dfrac{7}{4} - \dfrac{1}{4} [/tex][tex] \dfrac{6}{4} lb[/tex]_____________________________Time taken to melt :[tex]\dfrac{1}{4} \: hr[/tex]_____________________________ Rate of change in weight of ice :[tex] \mathrm{ \dfrac{change \: \: in \: \: weight}{time \: taken} }[/tex][tex] \dfrac{6}{4} \div \dfrac{1}{4} [/tex][tex] \dfrac{6}{4} \times 4[/tex][tex]6[/tex]The rate of change in weight of Ice is 6 lbs per hour ( 6 lb / h )_____________________________[tex]\mathrm{ \#TeeNForeveR}[/tex]

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