An unknown sample of a mixture of salt and sand weighs 7.52 g before washing with water and 3.45 g after. What is the percent of sand in the sample? (Show all work.)

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Question:

An unknown sample of a mixture of salt and sand weighs 7.52 g before washing with water and 3.45 g after. What is the percent of sand in the sample? (Show all work.)

Answers

Answer:An unknow sample has 45.9 % sand and 54.1% salt.Explanation:Step 1: Given dataAn unknown mixture of salt and sand weighs 7.52 g before washing with water;After washing with water, this mixture weighs 3.45gStep 2: Calculate mass of sandThe difference between the mass before and after washing, gives the amount of salt in the mixture. This because salt (NaCl) is soluble in water, but sand is insoluble. As final result, leaving only the sand behind.⇒7.52 - 3.45 = 4.07gStep 3: Calculate percentage of sandTo find the percentage of sand that was mixed with salt =Dividing the mass of sand by the total mass of the mixture= (3.45 g sand / 7.52g of mixture) X 100 = 45.9% sandStep 4: Calculate percentage of salt:If there is 45.9 % sand, this means there is 100% - 45.9 = 54.1% salt.We can control this by dividing the calculated mass of salt (4.07g) by the total mass of the mixture =(4.07 g of salt / 7.52g of mixture) X 100 = 54.1% saltAn unknow sample has 45.9 % sand and 54.1% salt.

Answer:Explanation:I think if you add you should get  the answer, Sorry if i'm not helpful.

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