An Olympic diver is on a diving platform 8.60 m above the water. To start her dive, she runs off of the platform with a speed of 1.23 m/s in the horizontal direction. What is the diver's speed (the sum of her horizontal and vertical velocities), in m/s, just before she enters the water?

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Question:

An Olympic diver is on a diving platform 8.60 m above the water. To start her dive, she runs off of the platform with a speed of 1.23 m/s in the horizontal direction. What is the diver's speed (the sum of her horizontal and vertical velocities), in m/s, just before she enters the water?

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Answer:13.1 m/sExplanation:If we assume that there is not air resistance then the horizontal component of velocity remains constant.  That is 1.23 m/sThe vertical component of final velocity can be calculated the following way:[tex]v_{yf} ^{2} =v_{yi}^{2}  +2ax\\[/tex][tex]v_{yf} = \sqrt{1.23^{2}+2*9.81*8.60} = 13.0 m/s[/tex]So the final velocity will be the square root of the sum of the squares of the componentv² = 1.23² + 13.0²v = 13.1 m/s

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