. An object is launched straight up into the air. It is launched from a height of H feet off the ground. Its height H, in feet, at t seconds is given by the equation H = -8t^2 + 40t + 18. Find all times t that the object is at a height of 50 feet off the ground.

1 answer
Question:

. An object is launched straight up into the air. It is launched from a height
of H feet off the ground. Its height H, in feet, at t seconds is given by the
equation H = -8t^2 + 40t + 18. Find all times t that the object is at a height
of 50 feet off the ground.

Answers

Answer:H=24Step-by-step explanation:

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