Answer:a. He can cut 5 strips of length 7/10 mb. He has 6/7 m of wire left over Step-by-step explanation:* Lets explain how to solve the problem- The length of the wire is 4.1 meters- We need to cut strips from this wire of 7/10 meter long- To do that lets divide the length of the wire by the length of each strip∵ The length of the wire = 4.1 meters∵ The length of each strip = 7/10 meter∴ The number of strips = 4.1 ÷ 7/10- Lets change the decimal number 4.1 to a fraction∵ 4.1 = 41/10∴ The number of strips = 41/10 ÷ 7/10- Multiply both terms by 10 to cancel the denominators∴ The number of strips = 41 ÷ 7∵ 41 ÷ 7 = 5 6/7 ∴ The number of strips = 5 6/7- That means the quotient is 5 and the reminder is 6a.∵ The quotient is the number of the strips∴ The number of strips is 5 * He can cut 5 strips of length 7/10 mb.∵ The (remainder/divisor) is the left over∴ The left over is 6/7* He has 6/7 m of wire left over
answer from Ashraf82
Answer:a. 5 stripsb. 0.6 metersStep-by-step explanation:a) to find number of 7/10 meter long strips, we have divide the total (4.1) by 7/10 and get the WHOLE NUMBER because the remainder is the remaining part.So[tex]\frac{4.1}{\frac{7}{10}}=5.85[/tex]So he can cut 5 stripsb)Since he can cut 5 strips, that would take [tex]\frac{7}{10}*5=3.5[/tex] m of the wire, the amount remaining is thus:4.1 - 3.5 = 0.6 m
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